# How do you write a quadratic equation with vertex at (-6,-2) and passes through point (-4,-14)?

##### 1 Answer

Jul 29, 2017

Equation is

#### Explanation:

A quadratic equation with a given vertex

#y=a(x-h)^2+k# or#x=a(y-k)^2+h#

As such as vertex is

The equation is either

If it is

and equation is

If it is

and equation is

graph{(y+3(x+6)^2+2)(72x-(y+2)^2+432)((x+6)^2+(y+2)^2-0.06)((x+4)^2+(y+14)^2-0.06)=0 [-19.67, 20.33, -19.28, 0.72]}